Q5.60 - Intermediate Algebra

Question

Multiply using Vertical method: $(6b-5)(7b-3)$

Step-by-Step Solution

Answer

$$\begin{gathered} Multiply the given binomials ,we get \\ (6b-5)(7b-3)=42b^2-53b+15 \end{gathered}$$

Step 1

$$\begin{gathered} Given Information \\ (6b-5)(7b-3) \end{gathered}$$

Step 2

Vertical addition is a method of adding where the numbers are lined up in columns according to their places value. 

Part(a) Step 1.Multiply binomial by vertical method

$$\begin{gathered} \left(a\right) \\ It doesn\text{'}t matter which binomial goes on the top. \\ 6b-5 \\ \frac{ \times 7b-3}{Mulitply 6b-5 by -3 -18b+15 } \\ \frac{Multiply 6b-5 by 7b 42b^2-35b }{ Add like terms 42b^2 -53b+15 } \end{gathered}$$