Q55E
Question
What mass of hydrogen gas results from the reaction of 8.5 g of \(KH\) with water?
\(KH{\rm{ }} + {\rm{ }}{H_2}O \to KOH{\rm{ }} + {\rm{ }}{H_2}\)
Step-by-Step Solution
VerifiedThe mass of the hydrogen gas is \(0.427\;g.\)
The molar massof a chemical compound is defined as the massof a sample of a compound divided by the amount of substance in that sample, measured in moles.
Conversion of mass, moles, and volume
- Molar mass of \({\rm{K}} = 39,0983\frac{{\rm{g}}}{{{\rm{mol}}}}.\)
- Molar mass of \({\rm{H}} = 1.00784\frac{g}{{\;{\rm{mol}}}}.\)
- Molar mass of \({\rm{KH}} = 40.106\frac{g}{{mol}}.\)
- Molar mass of \({H_2} = 2.016\frac{g}{{mol}}.\)
Since we see from the reaction formula that one mol of \(KH\)gives one mol of \({{\rm{H}}_2}\), we can make a proportion based on the molar masses of the givenmolecules.
Molar mass \({\rm{KH}}\) : Molar mass\({H_2}\) = mass \({\rm{KH}}\): mass\({H_2}.\)
\(\begin{aligned}{\underline{\phantom{xx}}}{\rm{Mass of }}{{\rm{H}}_{\rm{2}}}{\rm{ = }}\frac{{{\rm{ Mass of KH}} \times {\rm{Molar mass of }}{{\rm{H}}_{\rm{2}}}}}{{{\rm{ Molar mass of KH }}}}\\ = \frac{{8.5g \times 2.016\frac{g}{{mol}}}}{{40.106\frac{g}{{mol}}}}\\ = 0.427\;{\rm{g}}{\rm{.}}\end{aligned}\)
Therefore, the mass of the hydrogen gas is\(0.427g.\)