Q54. - Algebra 2

Question

Chaz has a collection of $15$ CDs. After he gets a part-time job, he decides to buy $3$ more CDs every time he goes to the music store. The function $C\left(t\right)=15+3t$ counts the number of CDs, $C\left(t\right)$ he has after $t$ trips to the music store. How many CDs will he have after he has been to the music store $8$ times?

Step-by-Step Solution

Answer

Chaz will have 39 CDs after he has been to the music store 8 times

Step 1 – Given information.

The given function of Chaz’s collection is:

$C\left(t\right)=15+3t$

Where $C\left(t\right)$ is the number of CDs he has after $t$ trips to the music store.

Step 2 – Substitute the given value in the given function.

Substitute $t=8$ in the function$C\left(t\right)=15+3t$.

$C\left(8\right)=15+3\left(8\right)$

Step 3 – Calculate the value by simplification.

$\begin{array}{l}C\left(8\right)=15+3\left(8\right)\\ C\left(8\right)=15+24\\ C\left(8\right)=39\end{array}$

Thus, Chaz will have 39 CDs after he has been to the music store 8 times.