Q53. - Algebra 1

Question

If the length of the rectangle is 28m and width of the rectangle is 17m. What is the perimeter of the new rectangle ABCD if each dimension is doubled?

Step-by-Step Solution

Answer

The perimeter of the new rectangle is $180\text{\hspace{0.17em}\hspace{0.17em}m}$.

Step 1. Given information.

Length of the rectangle = 28m,

Width of the rectangle = 17m

Step 2. Write the formula.

The perimeter of a rectangle is given by the following formula:

$P=2\left(l+w\right)$

Here l and w be the length and width of the rectangle respectively.

Step 3. Write new dimensions.

If the dimension of the rectangle is doubled.

Then,

Length of new rectangle = 56m,

Width of new rectangle = 34m

Step 4. Find the perimeter.

The perimeter of the new rectangle is given by,

$$\begin{gathered} P=2\left(56+34\right) \\ =2\left(90\right) \\ =180\text{\hspace{0.17em}\hspace{0.17em}m} \end{gathered}$$