Q50 E
Question
Using the MO diagrams, predict the bond order for the stronger bond in each pair:
B2 or B2+
F2 or F2+
O2 or O2 2+
C2+ or C2 -
Step-by-Step Solution
Verified- B2 has the strongest bond
- F2+ has the strongest bond
- O2 2+ has the strongest bond
- C2 - has the strongest bond
An ion is an electric charge-carrying atom or molecule. A superscript to represent the sign and size of an ion's electric charge is used to identify it.
The formula for bond order,
\begin{aligned}\texttt{Bond order}=\frac{(number of bonding electrons)-(number of antibonding electrons)}{2}\end{aligned}
As the bond order grows, the bond's strength grows as well.
a) B2 has the highest bond order, making it the most powerful bond.
Molecule | Bond order |
B2 | 1 |
B2+ | 0.5 |
Since F2+ has the greatest bond order, it has the strongest bond.
Molecule | Bond order |
F2 | 1 |
F2+ | 1.5 |
Since O22+ has the greatest bond order, it has the strongest bond.
Molecule | Bond order |
O2 | 2 |
O22+ | 3 |
C2- has the strongest bond since it has the greatest bond order.
Molecule | Bond order |
C2+ | 1.5 |
C2- | 2.5 |