Q.5

Question

Thousands of travelers pass through the airport in Guadalajara, Mexico, each day. Before leaving the airport, each passenger must pass through the Customs inspection area. Customs agents want to be sure that passengers do not bring illegal items into the country. But they do not have time to search every traveler’s luggage. Instead, they require each person to press a button. Either a red or a green bulb lights up. If the red light shows, the passenger will be searched by Customs agents. A green light means “go ahead.” Customs agents claim that the proportion of all travelers who will be stopped (red light) is 0.30, because the light has probability 0.30 of showing red on any push of the button. To test this claim, a concerned citizen watches a random sample of 100 travelers push the button. Only 20 get a red light.

(a) Assume that the Customs agents’ claim is true. Find the probability that the proportion of travelers who get a red light is as small as or smaller than the result in this sample. Show your work. 

(b) Based on your results in (a), do you believe the Customs agents’ claim? Explain. 

Step-by-Step Solution

Verified
Answer

(a) Probability is 0.0145

(b)The researcher does not believe the customs agent claim.

1Part(a) Step 1: Given information

Given in the question that, Thousands of travelers pass through the airport in Guadalajara, Mexico, each day. Before leaving the airport, each passenger must pass through the Customs inspection area. Customs agents want to be sure that passengers do not bring illegal items into the country. But they do not have time to search every traveler’s luggage. Instead, they require each person to press a button. Either a red or a green bulb lights up. If the red light shows, the passenger will be searched by Customs agents. A green light means “go ahead.” Customs agents claim that the proportion of all travelers who will be stopped (red light) is 0.30, because the light has probability 0.30 of showing red on any push of the button. To test this claim, a concerned citizen watches a random sample of 100 travelers push the button. Only 20  get a red light

2Part(a) Step 2: Explanation

Given,

Probability of success (p)=0.30

Number of events (x)=20

Number of trials (n)=100

If Xis a random variable represented as the number of people who get the red light.

Since, n p( mean) and n p(1-p) (variance) are greater than 5 . Therefore, Xwill follow Normal approximation.

X~N(np,np(1-p))

X~N(100(0.30),100(0.30)(1-0.30))

X~N(30,21)

The probability that the proportion of travelers who get a red light less than 20 , can be calculated as

P(X<20)=PX-npnp(1-p)<20-30214.5826                 =P(Z<-2.1822)                 =0.0145  (From standard normal table)

Thus, the required probability is 0.0145

3Part(b) Step 3: Given information

Given in the question that,  Thousands of travelers pass through the airport in Guadalajara, Mexico, each day. Before leaving the airport, each passenger must pass through the Customs inspection area. Customs agents want to be sure that passengers do not bring illegal items into the country. But they do not have time to search every traveler’s luggage. Instead, they require each person to press a button. Either a red or a green bulb lights up. If the red light shows, the passenger will be searched by Customs agents. A green light means “go ahead.” Customs agents claim that the proportion of all travelers who will be stopped (red light) is 0.30, because the light has probability 0.30 of showing red on any push of the button. To test this claim, a concerned citizen watches a random sample of 100 travelers push the button. Only 20 get a red light. 

4Part(b) Step 4: Explanation

From the above part, the probability is 0.0146. Since, the probability is low subsequently it seems, by all accounts, to be that the claim is false, Thus, the specialist doesn't completely accept that that the customs agent claim.