Q5. - Algebra 2

Question

Find the values of six trigonometric functions for angle $\left(\theta \right)$ shown below.

Step-by-Step Solution

Answer

The six trigonometric functions are: $\sin \theta =\frac{\sqrt{85}}{11},\csc \theta =\frac{11}{\sqrt{85}},\cos \theta =\frac{6}{11},\sec \theta =\frac{11}{6},\tan \theta =\frac{\sqrt{85}}{6},\cot \theta =\frac{6}{\sqrt{85}}$.

Step 1. Write down the given information.

The given figure is shown below.

Step 2. Concept used.

The six trigonometric functions are $\sin \theta , \csc \theta , \cos \theta , \sec \theta , \tan \theta , \cot \theta$.  

Let $(x,y)$ be a point in X-Y plane and (r) be the length of a line segment drawn from the origin to the point.

In, $\Delta OAB,OA=r, OB=x, AB=y$

Therefore, six trigonometric functions are;

$\begin{array}{c}\sin \theta =\frac{AB}{OA}=\frac{y}{r},\csc \theta =\frac{1}{\sin \theta }=\frac{OA}{AB}=\frac{r}{y}\\ \cos \theta =\frac{OB}{OA}=\frac{x}{r},\sec \theta =\frac{1}{\cos \theta }=\frac{OA}{OB}=\frac{r}{x}\\ \tan \theta =\frac{AB}{OB}=\frac{y}{x},\cot \theta =\frac{1}{\tan \theta }=\frac{OB}{AB}=\frac{x}{y}\end{array}$                                  

Step 3. Calculation.

From the given figure, the hypotenuse is evaluated as:

$\begin{array}{c}\text{Height}=\sqrt{{11}^2-6^2}\\ =\sqrt{85}\end{array}$

Now, the six trigonometric functions are evaluated as:

$\begin{array}{c}\sin \theta =\frac{\sqrt{85}}{11}\csc \theta =\frac{11}{\sqrt{85}}\\ \cos \theta =\frac{6}{11}\sec \theta =\frac{11}{6}\\ \tan \theta =\frac{\sqrt{85}}{6}\cot \theta =\frac{6}{\sqrt{85}}\end{array}$

Step 4. Conclusion.

The six trigonometric functions are: $\sin \theta =\frac{\sqrt{85}}{11},\csc \theta =\frac{11}{\sqrt{85}},\cos \theta =\frac{6}{11},\sec \theta =\frac{11}{6},\tan \theta =\frac{\sqrt{85}}{6},\cot \theta =\frac{6}{\sqrt{85}}$