Q4E

Question

A loud factory machine produces sound having a displacement amplitude of 1.00 μ-m, but the frequency of this sound can be adjusted. In order to prevent ear damage to the workers, the maxi mum pressure amplitude of the sound waves is limited to 10.0 Pa. Under the conditions of this factory, the bulk modulus of air is 1.42 x 105 Pa. What is the highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit? Is this frequency audible to the workers?

Step-by-Step Solution

Verified
Answer

The highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit is, f = 3.86 x 10³ Hz. Since f is in the range of [20 Hz - 20,000 Hz] which is the range of audible frequencies, the frequency is audible to the workers.

1Step 1: Determination of the formula for Sound and Hearing

The relation that describes the pressure amplitude for a sound wave is 
 
Pmax=BkA --(1)
 
 Where the bulk modulus of the air is B=1.42×105 Pa and the displacement amplitude of the waves produced by the machine is 1 μ-m. 
 
 Use equation (1) to calculate and then use k to determine the wavelength of the wave,  

λ=2πλ
 
Substitute into equation (1) with 10 Pa for Pmax, 1.42 x 105 Pafor B and 1 x 10-6 m for A:
k=10Pa1.42×105 Pa×1×10-6 mk=70.4m-1 
 
 Use the following relation to calculate the wavelength:


λ=2πk  =2π70.4m-1λ=0.089m

 

 Finally, the relation between the wavelength and the frequency of a sound wave is given by the following equation:

 

f=vλf=344m/s0.089mf=3.86×103 Hz 

2Step 2: Determination of whether the frequency is audible

Since is in the range of [20 Hz - 20,000 Hz] which is the range of audible frequencies, the frequency is audible. 
 
 
 Therefore, the highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit is, f = 3.86 x 10³ Hz. Since f is in the range of [20 Hz - 20,000 Hz] which is the range of audible frequencies, the frequency is audible to the workers.