Q4.93P - Chemistry: Molecular Nature Of Matter And Change

Question

Predict the product(s) and write a balanced equation for each of the following redox reactions:

$\mathbf{\left(}\mathbf{a}\mathbf{\right)}{\mathit{N}}_{\mathbf{2}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{+}{\mathit{H}}_{\mathbf{2}}\mathbf{\left(}\mathbf{g}\mathbf{\right)}\mathbf{\to }$

$\mathbf{\left(}\mathbf{b}\mathbf{\right)}\mathit{N}\mathit{a}\mathit{C}\mathit{l}{\mathit{O}}_{\mathbf{3}}\mathbf{\left(}\mathbf{s}\mathbf{\right)}\stackrel{\mathbf{\Delta }}{\mathbf{\to }}$

$\mathbf{\left(}\mathbf{c}\mathbf{\right)}\mathit{B}\mathit{a}\mathbf{\left(}\mathbf{s}\mathbf{\right)}\mathbf{+}{\mathit{H}}_{\mathbf{2}}\mathit{O}\mathbf{\left(}\mathbf{l}\mathbf{\right)}\mathbf{\to }$

Step-by-Step Solution

Answer

The product and the balance equation of the given reactions are:

(a)$N_2\left(g\right)+3H_2\left(g\right)\to 2N{H}_3\left(g\right)$

(b)$NaCl{O}_3\left(s\right)\stackrel{\Delta }{\to }2NaCl\left(s\right)+3O_2\left(g\right)$

(c)$Ba\left(s\right)+2H_{2}O\left(l\right)\to Ba{\left(OH\right)}_2\left(aq\right)+H_2\left(g\right)$

Step 1: Determine the product of the equation (a)

The given redox reaction is a combination reaction.

Nitrogen combines with hydrogen and forms ammonia.

 

The given reaction is:

$N_2\left(g\right)+H_2\left(g\right)\to$

The balanced reaction is:

$N_2\left(g\right)+3H_2\left(g\right)\to 2N{H}_3\left(g\right)$

Step 2: Determine the product of the equation (b)

The given redox reaction is a decomposition reaction.

Sodium chloratedecomposes and forms sodium chloride and oxygen.

 

The given reaction is:

$NaCl{O}_3\left(s\right)\stackrel{\Delta }{\to }$

The balanced reaction is:

$NaCl{O}_3\left(s\right)\stackrel{\Delta }{\to }2NaCl\left(s\right)+3O_2\left(g\right)$

Step 5: Determine the product of the equation (c)

The given redox reaction is a displacement reaction.

Hydrogen is displaced by Barium to form$\text{Ba}{\left(\text{OH}\right)}_{\text{2}}$ 

 

The given reaction is:

$Ba\left(s\right)+H_{2}O\left(l\right)\to$

The balanced reaction is:

$Ba\left(s\right)+2H_{2}O\left(l\right)\to Ba{\left(OH\right)}_2\left(aq\right)+H_2\left(g\right)$