Q49. - Algebra 2

Question

Find each value if $f\left(x\right)=3x-5$ and $g\left(x\right)=x^2-x$.

 

$f\left(\frac{2}{3}\right)$

Step-by-Step Solution

Answer

The value of $f\left(\frac{2}{3}\right)$ is $-3$.

Step 1 – Select the correct function.

_{The given functions are:}

$\begin{array}{l}f\left(x\right)=3x-5\\ g\left(x\right)=x^2-x\end{array}$

_{The required function for the value $f\left(\frac{2}{3}\right)$} is$f\left(x\right)=3x-5$.

Step 2 – Substitute the value in the selected function.

Substitute $x=\frac{2}{3}$ in the function $f\left(x\right)$.

$f\left(\frac{2}{3}\right)=3\left(\frac{2}{3}\right)-5$

Step 3 – Calculate the value by simplification.

$\begin{array}{l}f\left(\frac{2}{3}\right)=3\left(\frac{2}{3}\right)-5\\ f\left(\frac{2}{3}\right)=2-5\\ f\left(\frac{2}{3}\right)=-3\end{array}$

Thus, the value of $f\left(\frac{2}{3}\right)$ is $-3$.