Q48. - Algebra 2

Question

Graph the line that satisfies each set of conditions.

Passes through origin parallel to graph of $x+y=10.$

Step-by-Step Solution

Answer

The graph of the required line is:

Step 1- Given information

A point origin $(0,0)$ and an equation $x+y=10$.

Step 2- Calculation

From given information,

A point $(0,0)$ and $x+y=10$

Here, x-intercept is:

$\begin{array}{l}x+0=10\\ \Rightarrow x=10\end{array}$

y- intercept is:

$\begin{array}{l}0+y=10\\ \Rightarrow y=10\end{array}$

Therefore, the line goes to 10 units below and 10 units right then.

So, the slope of the line is$-\frac{10}{10}=-1$

We get a new point $\left(10,-10\right)$.

Now we draw the line which is contained both the points origin $(0,0)$ and $\left(10,-10\right)$.

Step 3- Graph of the line

The graph of the required line is: