Q47. - Algebra 2

Question

Perform the indicated matrix operations. If the matrix does not exist, write impossible47. $3\left[\begin{array}{cc}4& -2\\ -1& 7\end{array}\right]$

Step-by-Step Solution

Answer

The answer is $\left[\begin{array}{cc}12& -6\\ -3& 21\end{array}\right]$

Step 1 - State the definition of a matrix.

A rectangular array of numbers arranged in rows and columns is called a matrix.

Step 2 - Solve the matrix.

To evaluate the matrix use scalar multiplication. 

 Scalar multiplication is the method in which matrix is multiplied by a constant called scalar.

 The matrix is:$3\left[\begin{array}{cc}4& -2\\ -1& 7\end{array}\right]$

Here, 3 is the scalar. Multiply each element of the matrix by 3.

$3\left[\begin{array}{cc}4& -2\\ -1& 7\end{array}\right]=\left[\begin{array}{cc}12& -6\\ -3& 21\end{array}\right]$

Step 3 - State the conclusion.

Therefore, the resultant matrix is $\left[\begin{array}{cc}12& -6\\ -3& 21\end{array}\right]$