Q47. - Algebra 2

Question

For Exercises 46-48, use the information on temperatures at the left.

 

 

What temperature corresponds to $\mathbf{20}{}^{\circ }\mathbf{C}$?

Step-by-Step Solution

Answer

The temperature that corresponds to $20{}^{\circ }C$ is $68{}^{\circ }F$.

Step 1 – State the concept

The functional value at a point is obtained by putting the value in the expression of the function.

Step 2 – List the given data

It is clear, from the given information, that the temperature of $0{}^{\circ }C$ is equivalent to the temperature of $32{}^{\circ }F$ and the temperature of $100{}^{\circ }C$ corresponds to the temperature of $212{}^{\circ }F$.

Step 3 – Compute the temperature

As obtained previously, the linear equation that corresponds the temperature in degree Celsius $x$ to the temperature in degree Fahrenheit $y$ is $y=\frac{9}{5}x+32$. Put $x=20$ in $y=\frac{9}{5}x+32$ to get

$\begin{array}{l}y=\frac{9}{5}\left(20\right)+32\\ =9\left(4\right)+32\\ =36+32\\ =68\end{array}$

This implies that the temperature that corresponds to $20{}^{\circ }C$ is $68{}^{\circ }F$.