Q.4.61

Question

The probability of being dealt a full house in a hand of poker is approximately .0014. Find an approximation for the probability that in 1000 hands of poker, you will be dealt at least 2 full houses. 

Step-by-Step Solution

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Answer

An approximation for the probability that in 1000 hands of poker, we will be dealt at least 2 full houses is 0.408.

1Step 1: Given information

We are given that we have n=1000 autonomous Hands of poker, wherein every one of them we have p=0.0014 probability to get a Whole House.

2Step 2: Calculation

So on intermediate, we will hold λ=np=1.4 Full Houses in this session. Hence, we can use the Poisson approximation to get the demand.

So, let Y~Pois(λ).

We have that

P(Y2)=1-P(Y=0)-P(Y=1)=1-e-λ-λe-λ0.408

3Step 3: Final answer

So there is approximately 0.408 probability to get at least two full houses in 1000 hands.