Q45P - Chemistry: Molecular Nature Of Matter And Change

Question

(a) T2248i (b) S3479e (c) B511Draw atomic depictions similar to those in Problem 2.43 for $\mathbf{\left(}\mathit{a}\mathbf{\right)}\mathbf{ }{}_{\mathbf{22}}{}^{\mathbf{48}}\mathit{T}\mathit{i}\mathbf{ }\mathbf{\left(}\mathit{b}\mathbf{\right)}\mathbf{ }{}_{\mathbf{34}}{}^{\mathbf{79}}\mathit{S}\mathit{e}\mathbf{ }\mathbf{\left(}\mathit{c}\mathbf{\right)}\mathbf{ }{}_{\mathbf{5}}{}^{\mathbf{11}}\mathit{B}$

Step-by-Step Solution

Answer

In an element A represents the mass number and while Z represents an atomic number of an element.               

(a) ${}_{22}{}^{48}Ti$ 

(b)  ${}_{34}{}^{79}Se$

(c) ${}_5{}^{11}B$       

Step 1: Solution for part (a)

 ${}_{22}{}^{48}Ti$

Given,

Atomic number = 22

Atomic mass = 48

Number of protons = Atomic number = 22

Number of electrons = 22

We know, 

Atomic mass = number of protons + number of neutrons 

So,

Number of neutrons = atomic mass – number of protons

Number of neutrons = 48 – 22 = 26

Step 2: Solution for part (b)

 ${}_{34}{}^{79}Se$

Given, 

Atomic number = 34

Atomic mass = 79

Number of protons = Atomic number = 34

Number of electrons = 34

We know, 

Atomic mass = number of protons + number of neutrons

So,

Number of neutrons = atomic mass – number of protons

Number of neutrons = 79 – 34 = 45

Step 3: Solution for part (c)

 ${}_5{}^{11}B$

Given, 

Atomic number = 5

Atomic mass = 11

Number of protons = Atomic number = 5

Number of electrons = 5

We know, 

Atomic mass = number of protons + number of neutrons 

So,

Number of neutrons = atomic mass – number of protons

Number of neutrons = 11 – 5 = 6