Q45.

Question

Triangle ABC has vertices with coordinates A-4,2, B-4,-3, and C3,-2. After a dilation triangle A'B'C' has coordinates A-12,6, B-12,-9, and C9,-6. How many times as great is the perimeter of A'B'C' as ABC?

 A 3  B 6  C 12   D 13

Step-by-Step Solution

Verified
Answer

Perimeter of A'B'C' is times as that of ABC

1Step 1 - Find vertex matrices for Δ A B C  and  Δ A ' B ' C '

Since, an ordered pair is represented by a column matrix and triangle has 3 ordered pair on vertices so required matrix has 2 rows and 3 columns.

Coordinates of ΔABC are A-4,2, B-4,-3, and C3,-2, so its vertex matrix is -4-432-3-2


Again, Coordinates of ΔA'B'C' are A'-12,6, B'-12,-9, and C'9,-6, so its vertex matrix is -12-1296-9-6

2Step 2 - Vertex matrix after dilation

Vertex matrix of triangle after dilation is product of scale factor k with vertex matrix of given triangle as shown below

k×443232=12129696

3Step 3 - Find value of scale factor

Multiply scale factor k with vertex matrix of given triangle and equate it equal to vertex matrix of image. As both matrices are equal so corresponding elements are equal, so equate corresponding elements to get value of k as shown below

 4k4k3k2k3k2k=121296964k=12k=3

So, perimeter of A'B'C' is 3 times as that of ABC