Q45. - Organic Chemistry

Question

Question: Draw Lewis structures for the nine isomers having a molecular formula${\mathbf{C}}_{\mathbf{3}}{\mathbf{H}}_{\mathbf{6}}\mathbf{O}$ , with all atoms having a zero formal charge.

Step-by-Step Solution

Answer

Answer

The Lewis structures of the nine isomers are given below:

                 

Step-by-Step Solution Step 1: Lewis structures

The valence electrons in a particular molecule can be depicted with the help of Lewis structures.

The lone pairs of a molecule are also shown in a Lewis structure.

Step 2: Resonance structures

Resonance structures help in understanding the bonding that is occurring in a particular molecule.

Step 3: Lewis structures of C 3 H 6 O

The double bond equivalence for the molecular formula ${\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O}$is given below:

$\begin{array}{rcl}\mathrm{D}.\mathrm{B}.\mathrm{E} & =& \frac{1}{2}\left[\left(2\times 3\right)+2-6\right]\\ & =& 1\end{array}$

Thus, the possible compounds for molecular formula ${\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O}$ can contain one cyclic ring or alicyclic double bond. Therefore, the possible isomers can be aldehydes, ketones, enols, and cyclic ethers. The isomers of ${\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O}$  are given below:

                             

                                 

                                        Representation of the isomers of  ${\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O}$ 

 

 

 The Lewis structures of ${\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O}$are given below:

                 

                              Representation of the Lewis structures of  ${\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O}$