Q43. - Algebra 2

Question

Find the value of each determinant.

43.

$\left|\begin{array}{cc}\mathbf{8}& \mathbf{6}\\ \mathbf{4}& \mathbf{8}\\ & \end{array}\right|$

Step-by-Step Solution

Answer

The value of the given determinant is 40.

Step 1 ­- Description of step.

The value of a second-order determinant can be found out by calculating difference of product of two diagonals.

$\left|\begin{array}{cc}a& b\\ c& d\end{array}\right|=ad-bc$

Step 2 ­- Find the value of the determinant.

The value of the determinant $\left|\begin{array}{cc}8& 6\\ 4& 8\end{array}\right|$is given by:

$\begin{array}{c}\left|\begin{array}{cc}8& 6\\ 4& 8\end{array}\right|=\left(8\right)\left(8\right)-\left(4\right)\left(6\right)\\ =64-24\\ =40\end{array}$

Step 3 ­- Description of step.

The value of the given determinant is 40.