Q4.3-4PE

Question

Since astronauts in orbit are apparently weightless, a clever method of measuring their masses is needed to monitor their mass gains or losses to adjust diets. One way to do this is to exert a known force on an astronaut and measure the acceleration produced. Suppose a net external force of 50.0 N is exerted and the astronaut’s acceleration is measured to be 0.893 m/s2.

(a) Calculate her mass.

(b) By exerting a force on the astronaut, the vehicle in which they orbit experiences an equal and opposite force. Discuss how this would affect the measurement of the astronaut’s acceleration. Propose a method in which recoil of the vehicle is avoided.

Step-by-Step Solution

Verified
Answer

(a) The mass of the astronaut is 56 kg.

(b) The vehicle will not recoil.

1Step 1: Concept of Newton’s second law of motion

The Newton’s second law of motion states that the acceleration of a system is directly proportional to the net external force acting on the system and is inversely proportional to the mass of the system. It is mathematically represented as:

 

Fnet=ma                     …….…….. (i)

 

where Fnet is the net force, m is the mass, and a is the acceleration.

2Step 2: Given Data
  • Acceleration of the astronaut = 0.893 m/s2.
  • Net external force = 50 N.
3Step 3: (a) Determine the mass of the astronaut

By putting values 50 N for Fnet and 0.893 m/s2 for a in equation (i) and we get,

 

50 N=m×0.893 m/s2m=50 kgm/s20.893 m/s2m=56 kg

 

Hence, the mass of the astronaut is 56 kg.

4Step 4: (b) Determine the relationship between the acceleration due to mass experienced by another source

Write the expression for determining the acceleration due to another source.

 

ameas=aastr.+avehicle

 

Here, ameasis the acceleration due to mass experienced by another source, aastr.. Is the acceleration of the astronaut, and avehicle is the acceleration of the vehicle.

 

 avehicle=mastr.aastr.mvehicle

 

When the force is exerted by another source, then the vehicle will not be able to recoil. Hence, the vehicle will not recoil.