Q42. - Algebra 1

Question

A solution is prepared by dissolving 24 milliliters of saline in 150 milliliters of pure solution. What is the percent of saline in the pure solution?

Step-by-Step Solution

Answer

The percent of saline in pure water is 16%

Step 1. Let x and y be the amount of saline and pure water.

$\begin{array}{l}\text{Amount of Saline }x=\text{ 24 ml}\\ \text{Amount of pure water }y=150\text{ ml}\end{array}$

Step 2. Formula used.

To find what percent is a number x of another number y, use the below formula

$\begin{array}{l}x\text{ is percent of }y=\frac{x\times 100}{y}\%\\ \text{Where }x\text{ and }y\text{ is integers}\end{array}$

Step 3. Calculate the percent of saline in pure water.

$\begin{array}{l}\text{Percent of saline in pure water }=\frac{24\times 100}{150}\%\\ =\frac{240}{15}\%\\ \text{Percent of saline in pure water }=16\%\end{array}$

Therefore, the percent of saline in pure water is 16%