Q42 E
Question
Predict the products of reducing the following molecules. In each case, identify the product that will result from the minimal decrease in oxidation state for the highlighted carbon atom:
Step-by-Step Solution
Verified- The oxidation state for the highlighted carbon atom is between +1 and -1
- The oxidation state for the highlighted carbon atom ranges from +2 to 0
- The oxidation state for the highlighted carbon atom ranges from+3 to+1
In organic chemistry, the reduction is the process through which an atom obtains protons and electrons.
Since it's a reduction process, it usually destroys existing C-O bonds.
The starting material is ethanal, an aldehyde with a carbonyl group that can be reduced.
Because of two bonds with more electronegative atoms and one bond with a less electronegative atom, it has an oxidation state of+1.
It is converted to primary alcohol during the reduction process.
We're familiar with that type of organization.
It now has two bonds, one with a more electronegative atom and the other with a less electronegative atom. This indicates that its oxidation state has changed to -1.
Reaction (a)
The starting material is 2-propanone, a ketone with a carbonyl group that can be reduced.
It will have an oxidation state of +2 because it has two bonds with a more electronegative element, oxygen.
As a result of the reduction process,
It will have an oxidation state 0 due to its single bonds, one with each more electronegative and electropositive atom.
Reaction (b)
The starting material is ethanoic acid, which is a carboxylic acid with a carboxyl group that can be reduced.
It will have an oxidation state of +3 because it has three bonds with a more electronegative element, oxygen.
Ethanal, an aldehyde, is the end product of this reduction process.
Because of two bonds with more electronegative atoms and one bond with a less electronegative atom, it has an oxidation state of+1.
Reaction (c)