Q4.140CP

Question

Question: The amount of ascorbic acid (vitamin C; C6H8O6) in tablets is determined by reaction with bromine and then titration of the hydrobromic acid with standard base:

 C6H8O6+Br2C6H6O6+2HBrHBr+NaOHNaBr+H2O

A certain tablet is advertised as containing 500 mg of vitamin C. One tablet was dissolved in water and reacted with Br2. The solution was then titrated with 43.20 mL of 0.1350 NaOH. Did the tablet contain the advertised quantity of vitamin C?

Step-by-Step Solution

Verified
Answer

Answer: Yes, the tablet contains the advertised quantity of vitamin C.

1Step 1: Overall reaction

The given reactions are,

 C6H8O6+Br2C6H6O6+2HBrHBr+NaOHNaBr+H2O


The overall reaction for above reactions is,

 C6H8O6+Br2C6H6O6+2HBrHBr+NaOHNaBr+H2O_________________________________________C6H8O6+Br2+NaOHC6H6O6+HBr+NaBr+H2O

 

So, the overall reaction is,  C6H8O6+Br2+NaOHC6H6O6+HBr+NaBr+H2O

2Step 2: Determination of quantity of vitamin C

The number of moles of NaOH are,

Moles=concentration×volume=0.1350M×0.0432L=0.00583mol 

 

From equation (1), 1 mol of C6H8O6 produces 2 moles of HBr.

So, moles of C6H8O6 are,

 12×0.00583mol=0.002916mol

 

The mass of C6H6O6 is,0.002916 mol

 

Thus, it is concluded that the tablet contains the advertised quantity of vitamin C.