Q4.101 P
Question
A mixture of KClO3 and KCl with a mass of 0.950 g was heated to produce O2. After heating, the mass of residue was 0.700g. Assuming all the KClO3 decomposed to KCl and O2, calculate the mass percent of KClO3 in the original mixture.
Step-by-Step Solution
VerifiedYou need to calculate the mass percent of KClO3 in the original mixture.
Potassium chlorate decomposes to produce potassium chloride and oxygen. The balanced equation is like
As you know,
Mass of oxygen produced = mass of mixture – mass of residue
According to the question;
Mass of mixture = 0.950g
Mass of residue = 0.700g
Now, Mass of oxygen produced
= (0.950 - 0.700)(g)
= 0.250(g)
Mass of O2 = 0.250g
Molecular mass of O2 = 32g/mol
Again you know,
Moles of O2
Hence, moles of O2 produced are 0.0078mol.
According to the balanced equation
2 moles of KClO3 produces 3 moles O2
Now, moles of KClO3
Hence, moles of KClO3 are 0.0052mol.
Moles of KClO3 = 0.0052mol
Molecular mass of KClO3 = 122.55g/mol
Again you know,
mass = moles x mass(molar)
Mass of KClO3
= 0.0052x122.55(g)
= 0.63726(g)
Hence, mass of KClO3 is 0.63726g.
Again you know,
Mass percent of KClO3
Hence, mass percent of KClO3 is 67.08%.
Hence, mass percent of KClO3 in the original mixture is 67.08%.