Q41. - Algebra 2

Question

Graph $y=3-\frac{1}{2}\cos \left(\theta \right)\text{ and }y=3+\frac{1}{2}\cos \left(\theta +\pi \right)$. How do the graphs compare?

Step-by-Step Solution

Answer

From the graph of the function $y=3-\frac{1}{2}\cos \left(\theta \right)\text{ and }y=3+\frac{1}{2}\cos \left(\theta +\pi \right)$ it can be interpreted that the graph of the functions $y=3-\frac{1}{2}\cos \left(\theta \right)\text{ and }y=3+\frac{1}{2}\cos \left(\theta +\pi \right)$ overlap each other.

Step 1. Write down the given information.

The given functions are $y=3-\frac{1}{2}\cos \left(\theta \right)\text{ and }y=3+\frac{1}{2}\cos \left(\theta +\pi \right)$.

Step 2. Concept used.

A function of the form:

$y=a\sin b\left(\theta -h\right)+k,y=a\cos b\left(\theta -h\right)+k \text{and }y=a\tan b\left(\theta -h\right)+k$ has vertical shift $\left(k\right)$. And, a period of $\frac{360°}{\left|b\right|} \text{or }\frac{2\pi }{\left|b\right|}$ for sine, cosecant, secant and cosine functions and a period of $\frac{180°}{\left|b\right|} \text{or }\frac{\pi }{\left|b\right|}$ for tangent and cotangent function. The phase shift for the functions is $\left(h\right)$.

The amplitude of secant, cosecant, tangent and cotangent functions is not defined.

The equation for the midline is written as, $y=k$. A midline is a new reference line when the parent graph is stretched vertically up or down and then the graph oscillates about new reference line called the midline.

Step 3. Explanation.

The given functions are $y=3-\frac{1}{2}\cos \left(\theta \right)\text{ and }y=3+\frac{1}{2}\cos \left(\theta +\pi \right)$.

The parent function $y=\cos \left(\theta \right)$ is stretched vertically upwards 3 units up and its amplitude is compressed from 1 unit to $\frac{1}{2}$ unit to get the transformed function $y=3-\frac{1}{2}\cos \left(\theta \right)$.

The parent function $y=\cos \left(\theta \right)$ is stretched vertically upwards 3 units up and its amplitude is compressed from 1 unit to $\frac{1}{2}$ unit. The parent function $y=\cos \left(\theta \right)$ is shifted towards left with a phase shift of $-\pi$.

Step 4. Sketch the graph of given function.

The graph of the functions $y=3-\frac{1}{2}\cos \left(\theta \right)\text{ and }y=3+\frac{1}{2}\cos \left(\theta +\pi \right)$ are shown below.

Step 5. Interpretation from the graph of the function.

From the graph of the function $y=3-\frac{1}{2}\cos \left(\theta \right)\text{ and }y=3+\frac{1}{2}\cos \left(\theta +\pi \right)$ it can be interpreted that the graph of the functions $y=3-\frac{1}{2}\cos \left(\theta \right)\text{ and }y=3+\frac{1}{2}\cos \left(\theta +\pi \right)$ overlap each other.