Q4.

Question

Graph each system of inequalities. Name the coordinates of the vertices of the feasible region. Find the maximum and minimum values of the given function for this region.

x0y0y2x+43x+y9f(x,y)=2x+y

Step-by-Step Solution

Verified
Answer

 Co-ordinates of the vertex of the feasible regionOABC are O0,0,A3,0,B1,6,C0,4.

The maximum and minimum value of the function fx,y=2x+y are 8 and 0 respectively.

1Step-1 –Concept of solving the linear inequalities

To solve the inequalities we convert the inequalities into linear equations and find the solutions of the equations to obtain the graph.

2Step-2 –Concept of shading the region

For shading the region, we choose a point. If the point satisfies the inequalities then the shaded region is towards the point otherwise, the shaded region is away from the point.

3Step-3 –Solving the inequalities

Given inequalities are

x0y0y2x+43x+y9

Their respective linear equations are x=0,y=0y=2x+4,3x+y=9.and4x+y=16.

The points which satisfy the equation y=2x+4 are 0,4 and-2,0.

The points, which satisfy the equation 3x+y=9 are 0,9 and 3,0.

4Step-4 –Evaluating the shaded region

We choose0,0 to get the shaded region. The point 0,0 satisfies all inequalities x0,y0,y2x+4,3x+y9

5Step-5 –Plotting the graph


Therefore, the graph for the inequalities is


The feasible region isOABC, where co-ordinates ofO,A,B,Care0,0,3,0,1,6,0,4respectively.

6Step-6 –Determination of maximum and minimum value

f(x,y)=2x+y.

At point O(0,0)

f(x,y)=0.

At point A(3,0)

f(x,y)=2(3)+0=6.

At point B(1,6)

f(x,y)=2(1)+6=2+6=8

At point C(0,4)

f(x,y)=2(0)+4=4.