Q.3.92

Question

The melting point of benzene is 5.5C and its boiling point is 80.1C. Sketch a heating curve for benzene from 0oC to 100oC

a. What is the state of benzene at 15C?

b. What happens on the curve at 5.5oC?

c. What is the state of benzene at 63oC?

d. What is the state of benzene at 98oC?

e. At what temperature will both liquid and gas be present?

Step-by-Step Solution

Verified
Answer

The graph is shown

a. liquid state

b. It will be parallel to the x-axis

c. liquid state

d. gaseous state

e. both liquid and gas be present at 80.1oC

1Step 1: Given Information

The melting point of benzene = 5.5oC

The boiling point of benzene = 80.1oC

2Step 2: Explanation

The graph is,

3Step 3: Explanation Part (a)

As per the temperature information given, the heating bend of benzene in the temperature range 0C to 100Cis drawn and from the bend, it is seen that the substance stays in a solid state up to and it began to liquefy at this temperature.

Subsequently at 15oCit will be in a liquid state.

4Step 4: Explanation Part (b)

At the melting point of any substance, the heating bend stays parallel to the x-axis for example heat added as the temperature of the substance stays unaltered until entire the mass of the substance is melted.

5Step 5: Explanation Part (c)

It will be in a liquid form at 63C as the melting point of benzene is 5.5C after which it turns liquid.

6Step 6: Explanation Part (d)

It will be in a gaseous form at 98oC as after reaching the boiling point it turns gaseous and the boiling point of benzene is 80.1C

7Step 7: Explanation Part (e)

Both liquid and gas be present at 80.1Cas both the states are present together as represented with a parallel line with the x-axis.