Q38P

Question


Figure 22-58shows a circular disk that is uniformly charged. The central axis is perpendicular to the disk face, with the origin at the disk. Figure 22-58gives the magnitude of the electric field along that axis in terms of the maximum magnitude Em at the disk surface. The axis scale is set byzs= 8.0 cm. What is the radius of the disk?



Step-by-Step Solution

Verified
Answer

The radius of the disk is.6.93 cm

1Step 1: The given data
  • A circular disk of uniform charge.
  • The central z-axis is perpendicular to the face of the disk.
  • Maximum magnitude of the electric field is.Em
  • The z-axis scale set is.zs=8 cm
2Step 2: Understanding the concept of electric field

Using the concept of the electric field at a point from the disk along its central axis, we can get the ratio of the electric field at a point and maximum electric field, thus solving it by substituting the given data, we can get the radius of the disk.

 

Formula:

The magnitude of the electric field produced by the disk at a point on its central axis,                          E=σ2εo1zz2+R2                                                  (i)

where,  = surface charge density

z = distance on the central axis of the disk  

R = Radius of the disk

3Step 3: Calculation of the disk

Using equation (i) for the electric field at a point from the disk and maximum electric field (atz=0), we can get that 

EEmax=1zz2+R212=1zz2+R2      (from graph,EEmax=12)zz2+R2=123z2=R2R=z3=4×3 cm        (z=4, from graph)=6.93 cm

Hence, the value of the radius of the disk is .6.93 cm