Q36-6TYU.
Question
A plant cell with a ΨS of -0.65 MPa maintains a constant
volume when bathed in a solution that has a ΨS of -0.30 MPaand is in an open container. The cell has a
(A) ΨP of +0.65 MPa.
(B) Ψ of -0.65 MPa.
(C) ΨP of +0.35 MPa.
(D) ΨP of 0 MPa.
Step-by-Step Solution
Verified(A) The statement "ΨP of +0.65 MPa" is false.
(B) The statement "Ψ of -0.65 MPa" is false.
(C) The statement "ΨP of +0.35 MPa" is true
(D) The statement "ΨP of 0 MPa." is false.
The water potential equation is expressed as Ψ = ΨS + ΨP, where ΨS is the solute potential and is the water potential (osmotic potential), while ΨP denotes the pressure potential.
A solution's solute potential (S) is inversely proportional to molarity. The solute potential is another term because solutes affect the osmotic potential in the osmosis direction. The solutes found in plants are typically made up of mineral ions and sugars.
Thus, the correct answer is ΨP= 0.35 MPa instead of +0.65 MPa because ΨS is given as -0.30 MPa
Therefore, the given statement is false.
It is given that the Ψ is water potential in a container open to the atmosphere is - 0.35 MPa and plant cell with a ΨS of -0.65 MPa.
Thus, Ψ is 0.35 MPa.
Therefore, the given statement is false.
Thus, the ΨP= +0.35 MPa.
Therefore, the given statement is true.
Thus, the given option is incorrect because ΨP= 0.35 MPa instead of ΨP= 0 MPa.
Therefore, the given statement is false.