Q35. - Algebra 2

Question

Find the value of each expression

35. $\frac{12\left(52÷2^2\right)}{6}-\frac{2}{3}$

Step-by-Step Solution

Answer

Value of $\frac{12\left(52÷2^2\right)}{6}-\frac{2}{3}$ is  $25\frac{1}{3}$

Step 1 - Order for simplification

To evaluate any expression involving more than one operation, follow the below order of operations:

• First evaluate expressions inside grouping symbols like parentheses ( ) or brackets [ ].
• Evaluate the exponents.
• Perform Multiplication and division from left to right.
• Perform addition and subtraction from left to right.

Step 2 - Simplify expression inside grouping symbol

To evaluate the value of the given expression, first simplify the expression inside the parenthesis and then simplify fraction as shown below

$\begin{array}{c}\frac{12\left(52÷2^2\right)}{6}-\frac{2}{3}=\frac{12\left(52÷4\right)}{6}-\frac{2}{3}\\ =\frac{12\left(13\right)}{6}-\frac{2}{3}\\ =\frac{156}{6}-\frac{2}{3}\\ =\frac{78}{3}-\frac{2}{3}\end{array}$

Step 3 - Subtract 2 3 from 78 3

Now, to simplify further subtract the numbers to get

 $\begin{array}{c}\frac{78}{3}-\frac{2}{3}=\frac{78-2}{3}\\ =\frac{76}{3}\\ =25\frac{1}{3}\end{array}$

Thus, value of $\frac{12\left(52÷2^2\right)}{6}-\frac{2}{3}$ is  $25\frac{1}{3}$