Q33. - Algebra 1

Question

SCHOOL A conference room can seat a maximum of 85 people. The principal and two counselors need to meet with the school's juniors to discuss college admissions. If each student must bring a parent with them, how many students can attend each meeting? Assume that each student has a unique set of parents.

Step-by-Step Solution

Answer

The solution of the given equation is r = 13.

Step 1. Definition.

Equation: An equation is a mathematical statement that two expressions are equal. An equation will always contain an equal sign with an expression on each side.

Step 2. formulation of equation.

The maximum seating capacity in the conference room is 85

The principal and two counselors need to meet the school’s junior 

Mandatory attendees $=3 \mathrm{...}\left(\mathrm{principal} \mathrm{and} 2 \mathrm{counselors}\right)$

Let the number of students be $x$

As each student can bring one parent, 

number of parents will be equal to the number of students i.e.

$x$

Therefore, the equation for maximum seating capacity will be-$x+x+3=85$   

Step 3. Description of steps.

$\begin{array}{l}x+x+3=85\\ \Rightarrow 2x=85-3\\ \Rightarrow 2x=82\\ \Rightarrow x=41\end{array}$

The number of students who can attend the meeting is 41.