Q33 E

Question






Question: At what approximate positions might the following compounds show

IR absorptions?

(A)



(b)




(c)



(d)



(e)



Step-by-Step Solution

Verified
Answer

Absorptions with intensities for each compound are listed below:

(a) Aromatic ring C=C 1450-1600 cm-1, aromatic ring C-H 3030 cm-1, carboxylic acid C=O 1710-1760 cm-1 , alcohol O-H 2500-3100 cm-1.


(b) Aromatic ring C=C 1450-1600 cm-1, aromatic ring C-H 3030 cm-1and aromatic ester 1715cm-1

(c)Aromatic ring C=C 1450-1600 cm-1, aromatic ring C-H 3030 cm-1, alcohol O-H 2500-3100cm-1 and nitrile .

(d) Alkene C=C 1640-1680cm-1 ,alkene =C-H 3020-3100 cm-1and ketone1715 cm-1

(e) Ester 1735 cm-1and ketone 1715cm-1

1Step 1: Infrared (IR) spectroscopy

Infrared spectroscopy is the study of the interaction betweenthe sample andIR radiation which brings about change in vibrational-rotational level. Therefore, it is also called rotational-vibrational spectroscopy.

  • It is a technique based on the vibrations of the atoms of a molecule.
  • The waves are electromagnetic in nature and interact with polarity of the chemical bonds of the molecule.

If there is no polarity in the molecule then the infrared interaction is inactive and the molecule does not produce any IR spectrum

2Step 2: IR absorption

In general, IR absorption iscaused by the interaction between the IR electric field vector and molecular dipole transition related to the molecular vibrations. Absorption is at maximum when the electric field vector and dipole transition moment are parallel to each other.

3Step 3: IR (infrared) absorptions shown by following compound

(a)

(a) Aromatic ring C=C 1450-1600cm-1, aromatic ring C-H 3030cm-1, carboxylic acid C=O 1710-1760 cm-1{"x":[[32,25,5,4,17,30,34],[42,42,43,43,49,58,66,66,66,65,72,82,85,84],[96,106],[113,120,121,121]],"y":[[56,40,52,94,110,106,95],[44,109,109,53,45,44,51,109,110,51,44,45,53,108],[42,42],[16,5,6,57]],"t":[[0,0,0,0,0,0,0],[0,0,0,0,0,0,0,0,0,0,0,0,0,0],[0,0],[0,0,0,0]],"version":"2.0.0"} , alcohol O-H 2500-3100cm-1.

(b)




b) Aromatic ring C=C 1450-1600cm-1, aromatic ring C-H 3030cm-1, and aromatic ester 1715 cm-1.

(c)



(c)Aromatic ring C=C 1450-1600 cm-1, aromatic ring C-H 3030cm-1, alcohol O-H 2500-3100 cm-1, and nitrile.

(d)


 


(e) 


(d) Alkene C=C 1640-1680 cm-1,alkene =C-H 3020-3100 cm-1, and ketone1715 cm-1.

 


(e) Ester 1735 and ketone 1715 cm-1.