Q3.136CP - Chemistry: Molecular Nature Of Matter And Change

Question

Calculate each of the following quantities:Number of atoms in 0.0015 mol of fluorine gas

Step-by-Step Solution

Answer

According to the question, there are 0.0015 mole of F atoms, and then we have 0.0015´6.022´10²³ atoms.

So final answer is 0.009033´10²³

Or, 9.033´10²⁶  of F atoms

But for calculating F₂ diatomic molecules then we have, 9.033´10²⁶ ´2 = 18.066´10²⁶  =1.81´10²¹ atoms.

Step1. Number of atoms present.

If there is one mole of F atoms, then there are 6.022140857´10²³ atoms.

Fluorine can form diatomic molecules  so there we have F₂ atoms twice as many atoms.

According to the question, there are 0.0015 mole of F atoms, and then we have 0.0015´6.022´10²³ atoms.

So final answer is 0.009033´10²³

Or, 9.033´10²⁶  of F atoms

But for calculating F₂ diatomic molecules then we have, 9.033´10²⁶ ´2 = 18.066´10²⁶  =1.81´10²¹ atoms.

Step2. Final calculation.

If there is one mole of F atoms, then there are 6.022140857´10²³ atoms.

Fluorine can form diatomic molecules  so there we have F₂ atoms twice as many atoms.

According to the question, there are 0.0015 mole of F atoms, and then we have 0.0015´6.022´10²³ atoms.

So final answer is 0.009033´10²³

Or, 9.033´10²⁶  of F atoms

But for calculating F₂ diatomic molecules then we have, 9.033´10²⁶ ´2 = 18.066´10²⁶  =1.81´10²¹ atoms.