Q3.130CP - Chemistry: Molecular Nature Of Matter And Change

Question

Box A represents one unit volume of solution A. Which box – B, C or D represents one unit volume after adding enough solvent to solution A to (a) triple its volume; (b) double its volume; (c)quadruple its volume?
 

Step-by-Step Solution

Answer

1. Box C
2. Box B
3. Box D

Step 1: Identification of box with triple volume than A.

Box A has twelveparticles with unit volume.If the volume is tripled, then the number of particles will be calculated as follows:

$1\text{unit volume}\times \frac{12\text{ particles}}{3\text{ unit volume}}=4 \text{particles}$

Hence, Box C has triple volume than A,as four particles are present in it.

Step 2: Identification of box with double volume than A

Box A has twelve particles with unit volume. If the volume is doubled then the number of particles will be calculated as follows:

$1\text{unit volume}\times \frac{12\text{ particles}}{\text{2 unit volume}}=6 \text{particles}$

Hence,Box B has a double volume of A , as six particles are present in it.

Step3: Identification of box with double volume than A

Box A has twelve particles with unit volume. If the volume isquadruple, then the number of particles will be calculated as follows:

$1 \text{unit volume}\times \frac{12\text{ particles}}{\text{4 unit volume}}=3 \text{particles}$

 Hence, Box D has aquadruple volume of A, as three particles are present in it.

Result:

1. Box C has triple volume than A
2. Box B has a double volume of A
3. Box D has aquadruple volume of A