Q3. - Algebra 1

Question

Write an equation of a line in slope-intercept form with the given slope and $\mathit{y}$-intercept. Then graph the equation.

 

Slope: , $\mathit{y}$-intercept: $\mathbf{-}\mathbf{1}$

Step-by-Step Solution

Answer

The equation in slope-intercept form is $\mathit{y}\mathbf{=}\frac{\mathbf{3}}{\mathbf{4}}\mathit{x}\mathbf{-}\mathbf{1}$ and the graph of the equation is:

Step 1. State the concept of standard form of an equation.

The slope-intercept form of a linear equation is $y=mx+b$, where $m$ is the slope and $b$ is the $y$-intercept.

Step 2. Write equation of a line in slope-intercept form.

To find the equation of a line in slope-intercept form substitute $\frac{3}{4}$ for $m$ and $-1$ for $b$ in the equation $y=mx+b$.

The equation of the straight line is:

$\begin{array}{l}y=mx+b\\ y=\frac{3}{4}x-1\end{array}$

Step 3. Graph the equation.

Plot this equation on the Cartesian plane.

Therefore, the equation of the straight line is $y=\frac{3}{4}x-1$ and the graph of the equation is drawn above.