Q3 PT. - Algebra 1

Question

Graph the function, and compare to the parent graph. State the domain and range.

$y=\sqrt{x}+5$

Step-by-Step Solution

Answer

The domain of $y=\sqrt{x}+5$ is $x\in [0,\infty )$ and the range is $y\in [5,\infty )$

Step 1. State the concept of parent graph.

Parent graph: The simplest form of the given function is called the parent function of that function and the graph of the parent function is called parent graph.

Step 2. State the concept of domain and range.

Domain: The set of all possible values for which given function defined is called domain.

 

Range: The set of all possible values of the given function is called range.

Step 3. Graph the function.

The given function is: $y=\sqrt{x}+5$

 

In order to graph a function, find few co-ordinates by substituting values of ‘x’ and find finding the respective values of ‘y’. 

 

$$\begin{gathered} \text{For\hspace{0.17em}\hspace{0.17em}}x=0, \\ y=\sqrt{0}+5 \\ =0+5 \\ =5 \end{gathered}$$

 

$$\begin{gathered} \text{For\hspace{0.17em}\hspace{0.17em}}x=1, \\ y=\sqrt{1}+5 \\ =1+5 \\ =6 \end{gathered}$$

 

$$\begin{gathered} \text{For\hspace{0.17em}\hspace{0.17em}}x=4, \\ y=\sqrt{4}+5 \\ =2+5 \\ =7 \end{gathered}$$

 

$$\begin{gathered} \text{For\hspace{0.17em}\hspace{0.17em}}x=9, \\ y=\sqrt{9}+5 \\ =3+5 \\ =8 \end{gathered}$$

 

$$\begin{gathered} \text{For\hspace{0.17em}\hspace{0.17em}}x=16, \\ y=\sqrt{16}+5 \\ =4+5 \\ =9 \end{gathered}$$

 

Values of ‘x	Values of ‘y’	$\left(x,y\right)$
0	0	(0,5)
1	6	(1,6)
4	7	(4,7)
9	8	(9,8)
16	9	(16,9)

 

Plot these co-ordinates on a coordinate plane and join those points to get the required graph.

Step 4. Comparison with the parent graph.

The parent function of $y=\sqrt{x}+5$ is $y=\sqrt{x}$

 

The value 5 is being added to the parent function $y=\sqrt{x}$ a value greater than 1. So the graph is translated up 5 units from the parent graph $y=\sqrt{x}$.

Step 5. State the domain and range.

Since ‘x’ is inside the root, the values inside the root must be positive.

 

Therefore, values of x is all positive real numbers including zero.

 

That is, $x\ge 0,\Rightarrow x\in [0,\infty )$.

 

Therefore, domain: $[0,\infty )$

 

Since the y-values are added by 5. So y takes all the positive real values starting from 5, including 5.

 

Therefore, $y\ge 5,\Rightarrow y\in [5,\infty )$

 

Therefore, Range: $[5,\infty )$