Q2PE - College Physics (Urone)

Question

A car is traveling at a speed of  $\mathbf{33}\mathbf{ }\mathbf{m}\mathbf{/}\mathbf{s}$. (a) What is its speed in kilometres per hour? (b) Is it exceeding the $\mathbf{90}\mathbf{ }\mathbf{km}\mathbf{/}\mathbf{h}$ speed limit?

Step-by-Step Solution

Answer

When a body moves and cover some distance with respect to the time elapsed, it is called the speed of that body.

Step 1: Defining concept of velocity

The pace at which a body's distance changes in relation to time is referred to as its velocity. Its SI equivalent is  m/s.

Given Data

Consider the given data as below.

Car speed, $\mathrm{v}=33 \mathrm{m}/\mathrm{s}$

Step 2: (a) Calculation of velocity in kilometers per hour

$$\begin{gathered} \mathrm{v}=\left(33\frac{\mathrm{m}}{\mathrm{s}}\right)\left(\frac{0.001 \mathrm{km}}{\left({\displaystyle \frac{1}{3600}}\right)\mathrm{h}}\right) \\ =118.7 \mathrm{km}/\mathrm{h} \end{gathered}$$

Step 3: Explanation of part (b)

Check if the velocity of  90 km/h  is exceeding the limit or not.

Yes, it exceeds the limit of  90 km/h.

Step 4: Conclusion

Hence, the car speed in m/s is $\mathrm{v}=118.7 \mathrm{km}/\mathrm{h}$ ; yes, it exceeds $90 \mathrm{km}/\mathrm{h}$ .