Q2P

Question

Calculate the amount of energy required to spin-flip a proton in a spectrometer operating at 300 MHz. Does increasing the spectrometer frequency from 200 to 300 MHz increase or decrease the amount of energy necessary for

resonance?

Step-by-Step Solution

Verified
Answer


The amount of energy at an operating frequency of 300 MHz is 1.20×10-4kJmol


Increasing the frequency from 200 MHz to 300 MHz increases the amount of energy needed for resonance. 


1Step 1: Nuclear Magnetic Resonance Spectroscopy

The original frequency needed for resonance depends on external magnetic field strength, the identity and electronic environment of the nucleus. If a very strong magnetic field is applied, the energy difference between the spin states is larger and high-frequency radiation is required for a spin-flip.

2Step 2: Converting the given frequency into units in option (a)

The spectrometer frequency is 300 MHz. 

300 MHz is equal to 3.0x10 Hz.

The wavelength can be found as:

λ=cν=3×1083.0×108Hz=1.0m



The energy can be found as:

E=1.20×10-4kJmol1.0=1.20×10-4kJmol

The amount of energy at an operating frequency of 300 HMz is 1.20×10-4kJmol


The wavelength for 200MHz can be given as:

λ=cν=3×1082.0×108Hz=1.5m


The energy can be found as:


E=1.20×10-4kJmol1.5=8×10-5kJmol



Increasing the frequency from 200 MHz to 300 MHz increases the amount of energy needed for resonance.