Q.288 - Intermediate Algebra

Question

In the following exercises, solve.

$\sqrt{4x-3}=7$

Step-by-Step Solution

Answer

The solution of the given equation is $x=13$.

Step 1. Given information.

The given equation is:

$\sqrt{4x-3}=7$

Step 2. Solve the equation.

Take square on both sides.

$\begin{array}{rcl}(\sqrt{4x-3}{)}^2& =& 7^2\\ 4x-3& =& 49\\ 4x& =& 49+3\\ 4x& =& 52\end{array}$

DIvide both sides by 4.

$\begin{array}{rcl}\frac{4x}{4}& =& \frac{52}{4}\\ x& =& 13\end{array}$

Step 3. Conclusion.

The solution of the given equation is $x=13$.