Q28.

Question

Write an equation in slope-intercept form for the line that satisfies each set of conditions

28. passes through -6,15, parallel to the graph of 2x+3y=1

Step-by-Step Solution

Verified
Answer

The slope intercept form of the line which passes through the point -6,15 and parallel to the graph of 2x+3y=1 is y=-23x+11

1Step-1 – Apply the concept of slope-intercept form and point slope form

The slope of a line is the ratio of the change in the y-coordinates to the change in the x- coordinates.

The slope-intercept form of the equation of a line is given by y=mx+b where is the slope and is the y-intercept.

The point slope form of a equation of a line is given by y-y1=m(x-x1)  where x1,y1 are the coordinates of a point on the line and m is the slope of the line.

2Step-2 – Convert the equation of the given line into slope-intercept form

Given line is 2x+3y=1.

In order to convert it into the slope intercept form, keep the variable y on the left hand side and bring rest of the things to the right hand side.

Therefore,

2x+3y=12x+3y2x=12x(subtract 2x from both sides)3y=12x

Divide both sides by 3,

3y3=12x3y=132x3y=23x+13

This is of the form y=mx+b

Hence, the slope is m=-23

3Step-3 – Find the equation using point-slope form

Given the point -6,15 and slope is m=-23.

Therefore by using the point slope form

yy1=mxx1y15=23x6y15=23(x+6)y15=23x+236

Simplifying further,

y15=23x123y15=23x4Add 15 on both sidesy15+15=23x4+15y=23x+11

This is in slope intercept form.