Q27. - Geometry

Question

$\overline{AM}$is a median of  $△ABC$

If $BC=16$ and$h=5$ , find the areas of $△ABC$ and $△AMB$

Step-by-Step Solution

Answer

The area of $△ABC$is$40sq.unit$  and $△ABC$ is $20sq.unit$

Step 1. Modify the given diagram.

Given that base b= and Height h=5

Step 2. Find the area of first triangle.

Area of triangle ABC can be found using the formula

$\begin{array}{l}A=\frac{1}{2}bh\\ A=\frac{1}{2}\left(16\right)\left(5\right)\\ A=40sq.unit\end{array}$

Step 3. Find the area of second triangle.

Area of triangle$△AMB$ can be found using the formula 

$\begin{array}{l}A=\frac{1}{2}bh\\ A=\frac{1}{2}\left(8\right)\left(5\right)\\ A=20sq.unit\end{array}$

Therefore, the area of$ABC$ is $40sq.unit$and area of$△AMB$ is $20sq.unit$