Q.2.55 - An Introduction to General, Organic, and Biological Chemistry

Question

Perform each of the following conversions using metric conversion factors: 

a. $44.2$ mL to liters 

b. $8.65$m to nanometers 

c. $5.2 \times {10}^8$g to megagrams 

d. $0.72$ Ks to milliseconds

Step-by-Step Solution

Answer

a. $0.0422 \mathrm{L}$

b. $8.65 \times {10}^9 \mathrm{nm}$

c. $5.2 \times {10}^2 \mathrm{Mg}$

d. $7.2 \times {10}^5 \mathrm{ms}$

Step 1: Part (a) Given Information

Unit conversion for mL to L

Step 2: Part (a) Explanation

The metric unit of volume is Liters$\left(\mathrm{L}\right)$. In hospitals or laboratories volume is measured in milliliters$\left(\mathrm{mL}\right)$.

$1 \mathrm{mL}=1000 \mathrm{L}$

So, 44.2 mL will be:

Step 1: Part (b) Given Information

Unit conversion of m to nm

Step 2: Part (b) Explanation

The metric and SI unit of length is meters $\left(\mathrm{m}\right)$

$1 \mathrm{m}={10}^{9 }\mathrm{nm}$

So, 8.65 m will be:

$8.65 \mathrm{m}=8.65\times {10}^9 \mathrm{nm}$

Step 1: Part (c) Given Information

Unit conversion of g into Mg

Step 2: Part (c) Explanation

In laboratories, the mass is measured in megagrams$\left(\mathrm{Mg}\right)$.

$1 \mathrm{g}={10}^{-6} \mathrm{Mg}$

So, $5.2 \times {10}^8 \mathrm{g}$ will be

$5.2\times {10}^8 \mathrm{g}=5.2\times {10}^8 \times {10}^{-6}=5.2\times {10}^2 \mathrm{Mg}$

Step 1: Part (d) Given Information

Unit conversion of Ks to ms

Step 2: Part (d) Explanation

The unit conversion for Ks into ms can be given as:

$1 \mathrm{Ks}={10}^7 \mathrm{ms}$

So, 0.72 Ks will be

$$\begin{gathered} 0.72 \mathrm{Ks}=0.72\times {10}^7 \mathrm{ms} \\ \mathrm{or} \\ 7.2\times {10}^5 \mathrm{ms} \end{gathered}$$