Q2.5-37PE
Question
Dragsters can actually reach a top speed of in only considerably less time than given in Example 2.10 and Example 2.11.
(a) Calculate the average acceleration for such a dragster.
(b) Find the final velocity of this dragster starting from rest and accelerating at the rate found in (a) for 402 m (a quarter mile) without using any information on time.
(c) Why is the final velocity greater than that used to find the average acceleration?
Hint: Consider whether the assumption of constant acceleration is valid for a dragster. If not, discuss whether the acceleration would be greater at the beginning or end of the run and what effect that would have on the final velocity.
Step-by-Step Solution
Verifieda) 32.6 m/s2
b) 162 m/s
c) The acceleration is strongest in the first few gears and gradually decreases as the gears are increased.
- Intial velocity U = 0.
- Final velocity V = 145.
- The taken to reach final velocity T = 4.45 s.
a)
Now to calculate the acceleration, we have the equation of acceleration
Here V is the final velocity, and U is the initial velocity.
Substituting values in the above expression, we get,
Hence the average acceleration of the dragster is 32.6 m/s2.
b)
Data given is:
Distance d = 402.
The dragster's final velocity can be calculated from the equation of motion as:
Here V is the final velocity, U is the initial velocity, a is the acceleration, and d is the traveled distance.
Substituting values in the above expression, we get,
Hence the final velocity is .
c)
For a dragster, the constant acceleration assumption is invalid.
Various gears on a dragster have different acceleration rates.
The acceleration is strongest in the first few gears and gradually decreases as the gears are increased.
As a result, it would accelerate at a slower pace than in the previous few meters, with a final velocity of less than 162 m/s.