Q24P
Question
Where would you expect each of the following compounds to absorb in the IR spectrum?
(a) 4-Penten-2-one (b) 3-Penten-2-one
(c) 2,2-Dimethylcyclopentanone (d) m-Chlorobenzaldehyde
(e) 3-Cyclohexenone (f) 2-Hexenal
Step-by-Step Solution
Verified(a) 4-penten-2-one shows IR absorption at 1715
(b) 3-penten-2-one shows IR absorption at 1685
(c) 2,2-Dimethylcyclopentanoneshows IR absorption at 1750
(d) m-Chlorobenzaldehyde shows IR absorption at 1705, 2720 and 2820
(e) 3-Cyclohexenone shows IR absorption at 1715
(f) 2-Hexenal shows IR absorption at 1705
The infrared spectroscopy (IR) region lies under 50 - 12500 , which is further divided into three more regions which are as follows:
- Near IR region,which is from 50 to 650
- Middle IR region, which is from 650 to 4000
- Far IR region, which is from 4000to 12500
The Middle IR region is classified under two more regions:
- Finger Print region (800 to 14,500 )
- Functional group region (14,500to 4000 )
4-penten-2-one is the ketone that is not alpha,beta-unsaturated as there is no double bond present between the alpha (carbon next to carbonyl carbon) and beta carbon of the 4-penten-2-one so it will show the infrared absorption at 1715 .
4-penten-2-one IR absorption at 1715
3-penten-2-one is the alpha, beta-unsaturated ketone (conjugate system); due to a double bond between alpha and beta carbon, it will show the infrared absorption at 1685 .
The decrease in the absorption frequency in conjugated systems is because the compound 3-penten-2-one is involved in resonance. The Delocalization of electron density into the carbonyl reduces the bond order of the C=O group, which lowers the bond order, the bond’s force constant, and, in turn, lowers its vibrational frequency.
3-penten-2-one IR absorption at 1685
2,2-Dimethylcyclopentanone is the cyclic ketone that is five-membered, and it will cause the angle strain in the carbonyl group as the ring size of the cyclic ketone is only five carbon long, which in turn increases the absorption position of the Infrared spectrum.
It will show the infrared absorption at 1750 .
2,2-Dimethylcyclopentanone IR absorption at 1750
m-Chlorobenzaldehyde is the aromatic benzene having formyl substituent and chlorine substituent at the meta position.
In m-Chlorobenzaldehyde, the angle strain in the carbonyl group is less as the ring size is six carbon long, which decreases the absorption position of the Infrared spectrum. Therefore it shows the infrared absorption at 1705 .
The compound is an aldehyde, showing two other absorptions at 2720 and 2820 .
m-Chlorobenzaldehyde IR absorption at 1705, 2720 and 2820
3-Cyclohexenone is the cyclic ketone that is not analpha,beta-unsaturated ketone unsaturated as there is no double bond present between the alpha (carbon next to carbonyl carbon) and beta carbon of the 4-penten-2-one so it will show the infrared absorption at 1715 .
3-Cyclohexenone IR absorption at 1715
2-Hexenal is the alpha, beta-unsaturated aldehyde (conjugate system); due to a double bond between alpha and beta carbon, it will show the infrared absorption at 1705 .
The decrease in the absorption frequency in conjugated systems is because the compound 3-penten-2-one is involved in resonance. The Delocalization of electron density into the carbonyl reduces the bond order of the C=O group, which lowers the bond order, the bond’s force constant, and, in turn, lowers its vibrational frequency.
2-Hexenal IR absorption at 1705