Q24.78P - Chemistry: Molecular Nature Of Matter And Change

Question

How many MeV are released per nucleus when ${\mathbf{\text{3.2×10}}}^{\mathbf{\text{ - 3}}}\mathbf{\text{ mol}}$ of chromium-$\mathbf{49}$ releases ${\mathbf{\text{8.11×10}}}^{\mathbf{\text{5}}}\mathbf{\text{ kJ}}$? 

Step-by-Step Solution

Answer

The energy released per nucleus is $\text{2.63MeV/}$nucleus.

Step 1: Identify given information

From the problem: How many MeV are released per nucleus when 3.2×10 - 3 mol of chromium- 49 releases 8.11×10 5 kJ ?

Step 2: Determine what to find

We identify the unknown quantity in this Chemistry problem and select the appropriate approach.

Step 3: Select the appropriate formula

Based on the given data and unknown, we choose the relevant equation from Chemistry.

Step 4: Substitute values and solve

Substituting known values into the equation, we perform the calculation.

Step 5: State the result

The result is: The energy released per nucleus is 2.63MeV/ nucleus.