Q24.75P - Chemistry: Molecular Nature Of Matter And Change

Question

A H nucleus decays with an energy of MeV. Convert this energy into (a) electron volts; (b) joules.

Step-by-Step Solution

Answer

$$\begin{gathered} \text{a) }1.861\times {10}^4 \text{eV} \\ \text{b) 2.981}\times {10}^{-15} \text{J} \end{gathered}$$

Step 1:To convert (a) electron volts (b) joules .

(a)

We have to convert $\text{0.01861 MeV}$ into electron volts.

$\text{1MeV} \text{ = } {\text{10}}^{\text{6}}\text{eV}$

$\text{0.01861 MeV} \text{=0.01861 MeV×}\frac{{\text{10}}^{\text{6}}\text{ eV}}{\text{1 MeV}}{\text{=1.861×10}}^{\text{4}}\text{ eV}$

(b)

We have to convert $\text{0.01861 MeV}$ into joules.

$\text{1MeV} \text{ = } {\text{1.602×10}}^{\text{ - 13}}\text{ J}$

$\text{0.01861 MeV} \text{ = } \text{0.01861 MeV×}\frac{{\displaystyle {\text{1.602×10}}^{\text{ - 13}}\text{ J}}}{{\displaystyle \text{1 MeV}}} \text{ = } \text{2.981}{\times 10}^{\text{ - 15}}\text{ J}$