Q.240. - Intermediate Algebra

Question

Find the product of the below expression.

$\left(p-3\right)\left(p+3\right)$

Step-by-Step Solution

Answer

The solution is $p^2-9$.

Step 1. Given information.

The given expression is $\left(p-3\right)\left(p+3\right)$.

Step 2. Simplify the expression by using the difference of squares a + b a - b = a 2 - b 2 .

Solve it as follows:

$$\begin{gathered} \left(p-3\right)\left(p+3\right)={\left(p\right)}^2-{\left(3\right)}^2 \\ \Rightarrow p^2-9 \end{gathered}$$

Step 3. Simplified expression.

Hence, the required expression is $p^2-9$.