Q24 E
Question
In Problems 23-28, determine whether Theorem 1 implies that the given initial value problem has a unique solution.
Step-by-Step Solution
Verified Answer
The hypotheses of Theorem 1 are satisfied.
It follows from the theorem that the given initial value problem has a unique solution.
1Step 1: Finding the partial derivative of the given relation concerning y.
Here, and .
2Step 2: Determining whether Theorem 1 implies the existence of a unique solution or not.
Now from Step 1, we find that both of the functions and are continuous in any rectangle containing the point , so the hypotheses of Theorem 1 are satisfied. It then follows from the theorem that the given initial value problem has a unique solution in an interval about of the form , where is some positive number.
Hence, Theorem 1 implies that the given initial value problem has a unique solution.
Other exercises in this chapter
Q19 E
Show that the equation (dydx)2+y2+4=0 has no (real-valued) solution.
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Determine which values of m the function ϕ(x)=emx is a solution to the given equation.(a) d2ydx2+6dydx+5y=0(b) d3ydx3+3d2ydx2View solution
Q25 E
In Problems 23-28, determine whether Theorem 1 implies that the given initial value problem has a unique solution.3xdxdt+4t=0, x(2)=-π
View solution Q26 E
In Problems 23-28, determine whether Theorem 1 implies that the given initial value problem has a unique solution.dxdt+cos x=sin t, x(π)=0
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