Q23PE
Question
α decay of 210Po, the isotope of polonium in the decay series of 238U that was discovered by the Curies. A favorite isotope in physics labs, since it has a short half-life and decays to a stable nuclide.
Step-by-Step Solution
VerifiedThe electron capture Decay equation of 210Po is \(_{84}^{210}{P_{126}} \to _{82}^{206}\;P{b_{124}} + _2^4H{e_2}\).
The amount of matter contained in an atom of an element is called its atomic mass.
A = N + Z
Where A is atomic mass number
Z is the number of protons in a nucleus
X is the symbol for the element
In the expression below:
\(_Z^A{X_N}\)
Z is the number of protons in a nucleus
X is the symbol for the element
210Po
We know that
A = N + Z
Where A is atomic mass number
The atomic mass of \(_{84}^{210}Po\) is 210 and
A = 210 Z = 84 N = 126
Thus,
A = 210 N = 126 - 2 = 124 Z = 84 - 2 = 82
Therefore, alpha Decay equation of 210Po is \(_{84}^{210}{P_{126}} \to _{82}^{206}\;P{b_{124}} + _2^4H{e_2}\).