Q23P - Fundamentals Of Physics

Question

Figure 22-47 shows two parallel non-conducting rings with their central axes along a common line. Ring 1 has uniform charge ${\mathit{q}}_{\mathit{1}}$ and radius R; ring 2 has uniform charge ${\mathit{q}}_{\mathbf{2}}$ and the same radius R. The rings are separated by distance $\mathit{d}\mathbf{=}\mathbf{3}\mathbf{.}\mathbf{00}\mathit{R}$.The net electric field at point P on the common line, at distance R from ring 1, is zero. What is the ratio ${\mathit{q}}_{\mathbf{1}}\mathbf{/}{\mathit{q}}_{\mathbf{2}}$?

Step-by-Step Solution

Answer

The value of the ratio is $q_1/q_2$ is 0.506.

Step 1: The given data

Two parallel non-conducting rings with their central axes along a common line:

• Ring 1 has a uniform charge $q_{\mathit{1}}$ and radius R.
• Ring 2 has a uniform charge $q_{\mathit{2}}$ with radius R.
• The separation distance, d=3R.
• The net electric field on the common line at point P, which is at a distance of R is zero. 

Step 2: Understanding the concept of electric field

Using the concept of the electric field at an axial pint, we can find the net electric field of the individual rings. Further simplifying the equation, we will get the ratio of the charges.

Formula:

The magnitude of the electric field at an axial point, 

$E=\frac{q}{4{\mathrm{\pi \epsilon }}_0{\left({\mathrm{d}}^2+R^{\mathit{2}}\right)}^{3/2}}$                                                  (i)

Where d is the distance of field point from the charge, R is the radius of the circular ring, q is charge of the particle.

Step 3: Calculation of the ratio of the charges

We use the expression of electric field, assuming both charges are positive at point P using equation (i) as follows: (net electric at R from ring 1 is zero.)

                   $E_{left ring}=E_{right ring}$

$$\begin{gathered} \frac{1}{4{\mathrm{\pi \epsilon }}_0} \frac{q_{1}R}{{\left(R^2+R^2\right)}^{{\displaystyle \frac{3}{2}}}}=\frac{1}{4\mathrm{\pi \epsilon }} \frac{q_2\left(2R\right)}{({\left(2R{)}^2+R^2\right)}^{3/2}} \\ \frac{q_1}{q_2}=2{\left(\frac{2}{5}\right)}^{3/2} \\ \approx 0.0506 \end{gathered}$$

Hence, the value of the required ratio is 0.506.