Q.2.13 - A First Course in Probability

Question

Suppose that a person chooses a letter at random from R E S E R V E and then chooses one at random from V E R T I C A L. What is the probability that the same letter is chosen?

Step-by-Step Solution

Answer

Probability of choosing letter which exist in both would be P(A intersection B)$=$P(A)$·$P(B)$=\frac{1}{56}$

Step 1. Finding probability of RESERVE

Probability of choosing letter from "RESERVE" is P(B)$=\frac{1}{7}$

Step 2. Finding probability of VERTICAL

Probability of choosing letter from "VERTICAL" is P(B)$=\frac{1}{8}$

Step 3. Finding probability of choosing a letter which exist in both

 Probability of choosing a letter which exist in both would be P(A intersection B)$=$P(A).P(B)$=\frac{1}{56}$